8-2(-2n+3)=4(n-1)

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Solution for 8-2(-2n+3)=4(n-1) equation: 



8-2(-2n+3)=4(n-1)

We move all terms to the left:

8-2(-2n+3)-(4(n-1))=0

We multiply parentheses

4n-(4(n-1))-6+8=0



We calculate terms in parentheses: -(4(n-1)), so:

4(n-1)

We multiply parentheses

4n-4

Back to the equation:

-(4n-4)



We add all the numbers together, and all the variables

4n-(4n-4)+2=0

We get rid of parentheses

4n-4n+4+2=0

We add all the numbers together, and all the variables

6!=0

There is no solution for this equation

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