8-2(-4x+2)=2(4x-3)+10

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Solution for 8-2(-4x+2)=2(4x-3)+10 equation: 



8-2(-4x+2)=2(4x-3)+10

We move all terms to the left:

8-2(-4x+2)-(2(4x-3)+10)=0

We multiply parentheses

8x-(2(4x-3)+10)-4+8=0



We calculate terms in parentheses: -(2(4x-3)+10), so:

2(4x-3)+10

We multiply parentheses

8x-6+10

We add all the numbers together, and all the variables

8x+4

Back to the equation:

-(8x+4)



We add all the numbers together, and all the variables

8x-(8x+4)+4=0

We get rid of parentheses

8x-8x-4+4=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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