8-2(3-x)=4x-2(x+1)

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Solution for 8-2(3-x)=4x-2(x+1) equation: 



8-2(3-x)=4x-2(x+1)

We move all terms to the left:

8-2(3-x)-(4x-2(x+1))=0

We add all the numbers together, and all the variables

-2(-1x+3)-(4x-2(x+1))+8=0

We multiply parentheses

2x-(4x-2(x+1))-6+8=0



We calculate terms in parentheses: -(4x-2(x+1)), so:

4x-2(x+1)

We multiply parentheses

4x-2x-2

We add all the numbers together, and all the variables

2x-2

Back to the equation:

-(2x-2)



We add all the numbers together, and all the variables

2x-(2x-2)+2=0

We get rid of parentheses

2x-2x+2+2=0

We add all the numbers together, and all the variables

4!=0

There is no solution for this equation

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