8-2(3x+1)+x=26

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Solution for 8-2(3x+1)+x=26 equation: 



8-2(3x+1)+x=26

We move all terms to the left:

8-2(3x+1)+x-(26)=0

We add all the numbers together, and all the variables

x-2(3x+1)-18=0

We multiply parentheses

x-6x-2-18=0

We add all the numbers together, and all the variables

-5x-20=0

We move all terms containing x to the left, all other terms to the right

-5x=20

x=20/-5

x=-4

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