8-2(3x-6)=8x-(4x-2)

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Solution for 8-2(3x-6)=8x-(4x-2) equation: 



8-2(3x-6)=8x-(4x-2)

We move all terms to the left:

8-2(3x-6)-(8x-(4x-2))=0

We multiply parentheses

-6x-(8x-(4x-2))+12+8=0



We calculate terms in parentheses: -(8x-(4x-2)), so:

8x-(4x-2)

We get rid of parentheses

8x-4x+2

We add all the numbers together, and all the variables

4x+2

Back to the equation:

-(4x+2)



We add all the numbers together, and all the variables

-6x-(4x+2)+20=0

We get rid of parentheses

-6x-4x-2+20=0

We add all the numbers together, and all the variables

-10x+18=0

We move all terms containing x to the left, all other terms to the right

-10x=-18

x=-18/-10

x=1+4/5

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