8-2(r+4)=-2r-2(2r-6)

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Solution for 8-2(r+4)=-2r-2(2r-6) equation:



8-2(r+4)=-2r-2(2r-6)
We move all terms to the left:
8-2(r+4)-(-2r-2(2r-6))=0
We multiply parentheses
-2r-(-2r-2(2r-6))-8+8=0
We calculate terms in parentheses: -(-2r-2(2r-6)), so:
-2r-2(2r-6)
We multiply parentheses
-2r-4r+12
We add all the numbers together, and all the variables
-6r+12
Back to the equation:
-(-6r+12)
We add all the numbers together, and all the variables
-2r-(-6r+12)=0
We get rid of parentheses
-2r+6r-12=0
We add all the numbers together, and all the variables
4r-12=0
We move all terms containing r to the left, all other terms to the right
4r=12
r=12/4
r=3

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