8-2(r+4)=-2r-2(2r-6)

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Solution for 8-2(r+4)=-2r-2(2r-6) equation: 



8-2(r+4)=-2r-2(2r-6)

We move all terms to the left:

8-2(r+4)-(-2r-2(2r-6))=0

We multiply parentheses

-2r-(-2r-2(2r-6))-8+8=0



We calculate terms in parentheses: -(-2r-2(2r-6)), so:

-2r-2(2r-6)

We multiply parentheses

-2r-4r+12

We add all the numbers together, and all the variables

-6r+12

Back to the equation:

-(-6r+12)



We add all the numbers together, and all the variables

-2r-(-6r+12)=0

We get rid of parentheses

-2r+6r-12=0

We add all the numbers together, and all the variables

4r-12=0

We move all terms containing r to the left, all other terms to the right

4r=12

r=12/4

r=3

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