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8-2(x+5)=2(x-1)
We move all terms to the left:
8-2(x+5)-(2(x-1))=0
We multiply parentheses
-2x-(2(x-1))-10+8=0
We calculate terms in parentheses: -(2(x-1)), so:We add all the numbers together, and all the variables
2(x-1)
We multiply parentheses
2x-2
Back to the equation:
-(2x-2)
-2x-(2x-2)-2=0
We get rid of parentheses
-2x-2x+2-2=0
We add all the numbers together, and all the variables
-4x=0
x=0/-4
x=0
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