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8-2x=2(3-x)+2
We move all terms to the left:
8-2x-(2(3-x)+2)=0
We add all the numbers together, and all the variables
-2x-(2(-1x+3)+2)+8=0
We calculate terms in parentheses: -(2(-1x+3)+2), so:We get rid of parentheses
2(-1x+3)+2
We multiply parentheses
-2x+6+2
We add all the numbers together, and all the variables
-2x+8
Back to the equation:
-(-2x+8)
-2x+2x-8+8=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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