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8-2x=5x(x-2)
We move all terms to the left:
8-2x-(5x(x-2))=0
We calculate terms in parentheses: -(5x(x-2)), so:We get rid of parentheses
5x(x-2)
We multiply parentheses
5x^2-10x
Back to the equation:
-(5x^2-10x)
-5x^2-2x+10x+8=0
We add all the numbers together, and all the variables
-5x^2+8x+8=0
a = -5; b = 8; c = +8;
Δ = b2-4ac
Δ = 82-4·(-5)·8
Δ = 224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{224}=\sqrt{16*14}=\sqrt{16}*\sqrt{14}=4\sqrt{14}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-4\sqrt{14}}{2*-5}=\frac{-8-4\sqrt{14}}{-10} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+4\sqrt{14}}{2*-5}=\frac{-8+4\sqrt{14}}{-10} $
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