8-3(2x-4)=2(x+6)

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Solution for 8-3(2x-4)=2(x+6) equation: 



8-3(2x-4)=2(x+6)

We move all terms to the left:

8-3(2x-4)-(2(x+6))=0

We multiply parentheses

-6x-(2(x+6))+12+8=0



We calculate terms in parentheses: -(2(x+6)), so:

2(x+6)

We multiply parentheses

2x+12

Back to the equation:

-(2x+12)



We add all the numbers together, and all the variables

-6x-(2x+12)+20=0

We get rid of parentheses

-6x-2x-12+20=0

We add all the numbers together, and all the variables

-8x+8=0

We move all terms containing x to the left, all other terms to the right

-8x=-8

x=-8/-8

x=1

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