8-3(4-2x)=5(x-2)

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Solution for 8-3(4-2x)=5(x-2) equation: 



8-3(4-2x)=5(x-2)

We move all terms to the left:

8-3(4-2x)-(5(x-2))=0

We add all the numbers together, and all the variables

-3(-2x+4)-(5(x-2))+8=0

We multiply parentheses

6x-(5(x-2))-12+8=0



We calculate terms in parentheses: -(5(x-2)), so:

5(x-2)

We multiply parentheses

5x-10

Back to the equation:

-(5x-10)



We add all the numbers together, and all the variables

6x-(5x-10)-4=0

We get rid of parentheses

6x-5x+10-4=0

We add all the numbers together, and all the variables

x+6=0

We move all terms containing x to the left, all other terms to the right

x=-6

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