8-3(4b-1)=2(b-5)-3b

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Solution for 8-3(4b-1)=2(b-5)-3b equation: 



8-3(4b-1)=2(b-5)-3b

We move all terms to the left:

8-3(4b-1)-(2(b-5)-3b)=0

We multiply parentheses

-12b-(2(b-5)-3b)+3+8=0



We calculate terms in parentheses: -(2(b-5)-3b), so:

2(b-5)-3b

We add all the numbers together, and all the variables

-3b+2(b-5)

We multiply parentheses

-3b+2b-10

We add all the numbers together, and all the variables

-1b-10

Back to the equation:

-(-1b-10)



We add all the numbers together, and all the variables

-12b-(-1b-10)+11=0

We get rid of parentheses

-12b+1b+10+11=0

We add all the numbers together, and all the variables

-11b+21=0

We move all terms containing b to the left, all other terms to the right

-11b=-21

b=-21/-11

b=1+10/11

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