8-3(4x-1)=-40

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Solution for 8-3(4x-1)=-40 equation:



8-3(4x-1)=-40
We move all terms to the left:
8-3(4x-1)-(-40)=0
We add all the numbers together, and all the variables
-3(4x-1)+48=0
We multiply parentheses
-12x+3+48=0
We add all the numbers together, and all the variables
-12x+51=0
We move all terms containing x to the left, all other terms to the right
-12x=-51
x=-51/-12
x=4+1/4

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