8-3(5x+1)=2(x-8)+4

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Solution for 8-3(5x+1)=2(x-8)+4 equation: 



8-3(5x+1)=2(x-8)+4

We move all terms to the left:

8-3(5x+1)-(2(x-8)+4)=0

We multiply parentheses

-15x-(2(x-8)+4)-3+8=0



We calculate terms in parentheses: -(2(x-8)+4), so:

2(x-8)+4

We multiply parentheses

2x-16+4

We add all the numbers together, and all the variables

2x-12

Back to the equation:

-(2x-12)



We add all the numbers together, and all the variables

-15x-(2x-12)+5=0

We get rid of parentheses

-15x-2x+12+5=0

We add all the numbers together, and all the variables

-17x+17=0

We move all terms containing x to the left, all other terms to the right

-17x=-17

x=-17/-17

x=1

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