8-3(k+5)=1+6(k-4)

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Solution for 8-3(k+5)=1+6(k-4) equation: 



8-3(k+5)=1+6(k-4)

We move all terms to the left:

8-3(k+5)-(1+6(k-4))=0

We multiply parentheses

-3k-(1+6(k-4))-15+8=0



We calculate terms in parentheses: -(1+6(k-4)), so:

1+6(k-4)

determiningTheFunctionDomain
6(k-4)+1

We multiply parentheses

6k-24+1

We add all the numbers together, and all the variables

6k-23

Back to the equation:

-(6k-23)



We add all the numbers together, and all the variables

-3k-(6k-23)-7=0

We get rid of parentheses

-3k-6k+23-7=0

We add all the numbers together, and all the variables

-9k+16=0

We move all terms containing k to the left, all other terms to the right

-9k=-16

k=-16/-9

k=1+7/9

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