8-3(x+1)=-4(4-x)

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Solution for 8-3(x+1)=-4(4-x) equation: 



8-3(x+1)=-4(4-x)

We move all terms to the left:

8-3(x+1)-(-4(4-x))=0

We add all the numbers together, and all the variables

-3(x+1)-(-4(-1x+4))+8=0

We multiply parentheses

-3x-(-4(-1x+4))-3+8=0



We calculate terms in parentheses: -(-4(-1x+4)), so:

-4(-1x+4)

We multiply parentheses

4x-16

Back to the equation:

-(4x-16)



We add all the numbers together, and all the variables

-3x-(4x-16)+5=0

We get rid of parentheses

-3x-4x+16+5=0

We add all the numbers together, and all the variables

-7x+21=0

We move all terms containing x to the left, all other terms to the right

-7x=-21

x=-21/-7

x=+3

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