8-3(y-4)=5y+2(y-6)

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Solution for 8-3(y-4)=5y+2(y-6) equation:



8-3(y-4)=5y+2(y-6)
We move all terms to the left:
8-3(y-4)-(5y+2(y-6))=0
We multiply parentheses
-3y-(5y+2(y-6))+12+8=0
We calculate terms in parentheses: -(5y+2(y-6)), so:
5y+2(y-6)
We multiply parentheses
5y+2y-12
We add all the numbers together, and all the variables
7y-12
Back to the equation:
-(7y-12)
We add all the numbers together, and all the variables
-3y-(7y-12)+20=0
We get rid of parentheses
-3y-7y+12+20=0
We add all the numbers together, and all the variables
-10y+32=0
We move all terms containing y to the left, all other terms to the right
-10y=-32
y=-32/-10
y=3+1/5

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