8-3(y-4)=5y+2(y-6)

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Solution for 8-3(y-4)=5y+2(y-6) equation: 



8-3(y-4)=5y+2(y-6)

We move all terms to the left:

8-3(y-4)-(5y+2(y-6))=0

We multiply parentheses

-3y-(5y+2(y-6))+12+8=0



We calculate terms in parentheses: -(5y+2(y-6)), so:

5y+2(y-6)

We multiply parentheses

5y+2y-12

We add all the numbers together, and all the variables

7y-12

Back to the equation:

-(7y-12)



We add all the numbers together, and all the variables

-3y-(7y-12)+20=0

We get rid of parentheses

-3y-7y+12+20=0

We add all the numbers together, and all the variables

-10y+32=0

We move all terms containing y to the left, all other terms to the right

-10y=-32

y=-32/-10

y=3+1/5

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