8-3(y-5)=-4(2y-7)

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Solution for 8-3(y-5)=-4(2y-7) equation: 



8-3(y-5)=-4(2y-7)

We move all terms to the left:

8-3(y-5)-(-4(2y-7))=0

We multiply parentheses

-3y-(-4(2y-7))+15+8=0



We calculate terms in parentheses: -(-4(2y-7)), so:

-4(2y-7)

We multiply parentheses

-8y+28

Back to the equation:

-(-8y+28)



We add all the numbers together, and all the variables

-3y-(-8y+28)+23=0

We get rid of parentheses

-3y+8y-28+23=0

We add all the numbers together, and all the variables

5y-5=0

We move all terms containing y to the left, all other terms to the right

5y=5

y=5/5

y=1

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