8-3(z-4)=2(z+3)

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Solution for 8-3(z-4)=2(z+3) equation: 



8-3(z-4)=2(z+3)

We move all terms to the left:

8-3(z-4)-(2(z+3))=0

We multiply parentheses

-3z-(2(z+3))+12+8=0



We calculate terms in parentheses: -(2(z+3)), so:

2(z+3)

We multiply parentheses

2z+6

Back to the equation:

-(2z+6)



We add all the numbers together, and all the variables

-3z-(2z+6)+20=0

We get rid of parentheses

-3z-2z-6+20=0

We add all the numbers together, and all the variables

-5z+14=0

We move all terms containing z to the left, all other terms to the right

-5z=-14

z=-14/-5

z=2+4/5

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