8-3x+1=4-(10-2x)

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Solution for 8-3x+1=4-(10-2x) equation: 



8-3x+1=4-(10-2x)

We move all terms to the left:

8-3x+1-(4-(10-2x))=0

We add all the numbers together, and all the variables

-3x-(4-(-2x+10))+8+1=0

We add all the numbers together, and all the variables

-3x-(4-(-2x+10))+9=0



We calculate terms in parentheses: -(4-(-2x+10)), so:

4-(-2x+10)

determiningTheFunctionDomain
-(-2x+10)+4

We get rid of parentheses

2x-10+4

We add all the numbers together, and all the variables

2x-6

Back to the equation:

-(2x-6)



We get rid of parentheses

-3x-2x+6+9=0

We add all the numbers together, and all the variables

-5x+15=0

We move all terms containing x to the left, all other terms to the right

-5x=-15

x=-15/-5

x=+3

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