8-4(-6-4x)=8(x+3)

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Solution for 8-4(-6-4x)=8(x+3) equation: 



8-4(-6-4x)=8(x+3)

We move all terms to the left:

8-4(-6-4x)-(8(x+3))=0

We add all the numbers together, and all the variables

-4(-4x-6)-(8(x+3))+8=0

We multiply parentheses

16x-(8(x+3))+24+8=0



We calculate terms in parentheses: -(8(x+3)), so:

8(x+3)

We multiply parentheses

8x+24

Back to the equation:

-(8x+24)



We add all the numbers together, and all the variables

16x-(8x+24)+32=0

We get rid of parentheses

16x-8x-24+32=0

We add all the numbers together, and all the variables

8x+8=0

We move all terms containing x to the left, all other terms to the right

8x=-8

x=-8/8

x=-1

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