8-4(2x-3)=8(x-1)

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Solution for 8-4(2x-3)=8(x-1) equation: 



8-4(2x-3)=8(x-1)

We move all terms to the left:

8-4(2x-3)-(8(x-1))=0

We multiply parentheses

-8x-(8(x-1))+12+8=0



We calculate terms in parentheses: -(8(x-1)), so:

8(x-1)

We multiply parentheses

8x-8

Back to the equation:

-(8x-8)



We add all the numbers together, and all the variables

-8x-(8x-8)+20=0

We get rid of parentheses

-8x-8x+8+20=0

We add all the numbers together, and all the variables

-16x+28=0

We move all terms containing x to the left, all other terms to the right

-16x=-28

x=-28/-16

x=1+3/4

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