8-4(x-1)=2(-x+3)

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Solution for 8-4(x-1)=2(-x+3) equation: 



8-4(x-1)=2(-x+3)

We move all terms to the left:

8-4(x-1)-(2(-x+3))=0

We add all the numbers together, and all the variables

-4(x-1)-(2(-1x+3))+8=0

We multiply parentheses

-4x-(2(-1x+3))+4+8=0



We calculate terms in parentheses: -(2(-1x+3)), so:

2(-1x+3)

We multiply parentheses

-2x+6

Back to the equation:

-(-2x+6)



We add all the numbers together, and all the variables

-4x-(-2x+6)+12=0

We get rid of parentheses

-4x+2x-6+12=0

We add all the numbers together, and all the variables

-2x+6=0

We move all terms containing x to the left, all other terms to the right

-2x=-6

x=-6/-2

x=+3

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