8-4x+12=3x-2(x-5)

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Solution for 8-4x+12=3x-2(x-5) equation: 



8-4x+12=3x-2(x-5)

We move all terms to the left:

8-4x+12-(3x-2(x-5))=0

We add all the numbers together, and all the variables

-4x-(3x-2(x-5))+20=0



We calculate terms in parentheses: -(3x-2(x-5)), so:

3x-2(x-5)

We multiply parentheses

3x-2x+10

We add all the numbers together, and all the variables

x+10

Back to the equation:

-(x+10)



We get rid of parentheses

-4x-x-10+20=0

We add all the numbers together, and all the variables

-5x+10=0

We move all terms containing x to the left, all other terms to the right

-5x=-10

x=-10/-5

x=+2

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