8-5(3-2x)=x-4(x+9)

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Solution for 8-5(3-2x)=x-4(x+9) equation: 



8-5(3-2x)=x-4(x+9)

We move all terms to the left:

8-5(3-2x)-(x-4(x+9))=0

We add all the numbers together, and all the variables

-5(-2x+3)-(x-4(x+9))+8=0

We multiply parentheses

10x-(x-4(x+9))-15+8=0



We calculate terms in parentheses: -(x-4(x+9)), so:

x-4(x+9)

We multiply parentheses

x-4x-36

We add all the numbers together, and all the variables

-3x-36

Back to the equation:

-(-3x-36)



We add all the numbers together, and all the variables

10x-(-3x-36)-7=0

We get rid of parentheses

10x+3x+36-7=0

We add all the numbers together, and all the variables

13x+29=0

We move all terms containing x to the left, all other terms to the right

13x=-29

x=-29/13

x=-2+3/13

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