8-5(3-2x)=x-4+10x

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Solution for 8-5(3-2x)=x-4+10x equation: 



8-5(3-2x)=x-4+10x

We move all terms to the left:

8-5(3-2x)-(x-4+10x)=0

We add all the numbers together, and all the variables

-5(-2x+3)-(11x-4)+8=0

We multiply parentheses

10x-(11x-4)-15+8=0

We get rid of parentheses

10x-11x+4-15+8=0

We add all the numbers together, and all the variables

-1x-3=0

We move all terms containing x to the left, all other terms to the right

-x=3

x=3/-1

x=-3

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