8-5(4-3x)=3(4-x)-8x

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Solution for 8-5(4-3x)=3(4-x)-8x equation: 



8-5(4-3x)=3(4-x)-8x

We move all terms to the left:

8-5(4-3x)-(3(4-x)-8x)=0

We add all the numbers together, and all the variables

-5(-3x+4)-(3(-1x+4)-8x)+8=0

We multiply parentheses

15x-(3(-1x+4)-8x)-20+8=0



We calculate terms in parentheses: -(3(-1x+4)-8x), so:

3(-1x+4)-8x

We add all the numbers together, and all the variables

-8x+3(-1x+4)

We multiply parentheses

-8x-3x+12

We add all the numbers together, and all the variables

-11x+12

Back to the equation:

-(-11x+12)



We add all the numbers together, and all the variables

15x-(-11x+12)-12=0

We get rid of parentheses

15x+11x-12-12=0

We add all the numbers together, and all the variables

26x-24=0

We move all terms containing x to the left, all other terms to the right

26x=24

x=24/26

x=12/13

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