8-5(y+1)=-2(3y-5)

Solution for 8-5(y+1)=-2(3y-5) equation:

8-5(y+1)=-2(3y-5)

We move all terms to the left:

8-5(y+1)-(-2(3y-5))=0

We multiply parentheses

-5y-(-2(3y-5))-5+8=0


We calculate terms in parentheses: -(-2(3y-5)), so:

-2(3y-5)

We multiply parentheses

-6y+10

Back to the equation:

-(-6y+10)


We add all the numbers together, and all the variables

-5y-(-6y+10)+3=0

We get rid of parentheses

-5y+6y-10+3=0

We add all the numbers together, and all the variables

y-7=0

We move all terms containing y to the left, all other terms to the right

y=7