8-5(y+2)=-2(5y-2)-2

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Solution for 8-5(y+2)=-2(5y-2)-2 equation: 



8-5(y+2)=-2(5y-2)-2

We move all terms to the left:

8-5(y+2)-(-2(5y-2)-2)=0

We multiply parentheses

-5y-(-2(5y-2)-2)-10+8=0



We calculate terms in parentheses: -(-2(5y-2)-2), so:

-2(5y-2)-2

We multiply parentheses

-10y+4-2

We add all the numbers together, and all the variables

-10y+2

Back to the equation:

-(-10y+2)



We add all the numbers together, and all the variables

-5y-(-10y+2)-2=0

We get rid of parentheses

-5y+10y-2-2=0

We add all the numbers together, and all the variables

5y-4=0

We move all terms containing y to the left, all other terms to the right

5y=4

y=4/5

y=4/5

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