8-5/7j=-32

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Solution for 8-5/7j=-32 equation:



8-5/7j=-32
We move all terms to the left:
8-5/7j-(-32)=0
Domain of the equation: 7j!=0
j!=0/7
j!=0
j∈R
We add all the numbers together, and all the variables
-5/7j+40=0
We multiply all the terms by the denominator
40*7j-5=0
Wy multiply elements
280j-5=0
We move all terms containing j to the left, all other terms to the right
280j=5
j=5/280
j=1/56

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