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8-5=2+3(x+3)
We move all terms to the left:
8-5-(2+3(x+3))=0
We add all the numbers together, and all the variables
-(2+3(x+3))+3=0
We calculate terms in parentheses: -(2+3(x+3)), so:We get rid of parentheses
2+3(x+3)
determiningTheFunctionDomain 3(x+3)+2
We multiply parentheses
3x+9+2
We add all the numbers together, and all the variables
3x+11
Back to the equation:
-(3x+11)
-3x-11+3=0
We add all the numbers together, and all the variables
-3x-8=0
We move all terms containing x to the left, all other terms to the right
-3x=8
x=8/-3
x=-2+2/3
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