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8-5b=5-4(b-2)
We move all terms to the left:
8-5b-(5-4(b-2))=0
We calculate terms in parentheses: -(5-4(b-2)), so:We get rid of parentheses
5-4(b-2)
determiningTheFunctionDomain -4(b-2)+5
We multiply parentheses
-4b+8+5
We add all the numbers together, and all the variables
-4b+13
Back to the equation:
-(-4b+13)
-5b+4b-13+8=0
We add all the numbers together, and all the variables
-1b-5=0
We move all terms containing b to the left, all other terms to the right
-b=5
b=5/-1
b=-5
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