8-6(3z-4)=5(8z+9)+8

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Solution for 8-6(3z-4)=5(8z+9)+8 equation: 



8-6(3z-4)=5(8z+9)+8

We move all terms to the left:

8-6(3z-4)-(5(8z+9)+8)=0

We multiply parentheses

-18z-(5(8z+9)+8)+24+8=0



We calculate terms in parentheses: -(5(8z+9)+8), so:

5(8z+9)+8

We multiply parentheses

40z+45+8

We add all the numbers together, and all the variables

40z+53

Back to the equation:

-(40z+53)



We add all the numbers together, and all the variables

-18z-(40z+53)+32=0

We get rid of parentheses

-18z-40z-53+32=0

We add all the numbers together, and all the variables

-58z-21=0

We move all terms containing z to the left, all other terms to the right

-58z=21

z=21/-58

z=-21/58

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