8-6(x+1)=6-4(x-2)

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Solution for 8-6(x+1)=6-4(x-2) equation: 



8-6(x+1)=6-4(x-2)

We move all terms to the left:

8-6(x+1)-(6-4(x-2))=0

We multiply parentheses

-6x-(6-4(x-2))-6+8=0



We calculate terms in parentheses: -(6-4(x-2)), so:

6-4(x-2)

determiningTheFunctionDomain
-4(x-2)+6

We multiply parentheses

-4x+8+6

We add all the numbers together, and all the variables

-4x+14

Back to the equation:

-(-4x+14)



We add all the numbers together, and all the variables

-6x-(-4x+14)+2=0

We get rid of parentheses

-6x+4x-14+2=0

We add all the numbers together, and all the variables

-2x-12=0

We move all terms containing x to the left, all other terms to the right

-2x=12

x=12/-2

x=-6

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