8-6(x-4)=2(4x-5)+22

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Solution for 8-6(x-4)=2(4x-5)+22 equation: 



8-6(x-4)=2(4x-5)+22

We move all terms to the left:

8-6(x-4)-(2(4x-5)+22)=0

We multiply parentheses

-6x-(2(4x-5)+22)+24+8=0



We calculate terms in parentheses: -(2(4x-5)+22), so:

2(4x-5)+22

We multiply parentheses

8x-10+22

We add all the numbers together, and all the variables

8x+12

Back to the equation:

-(8x+12)



We add all the numbers together, and all the variables

-6x-(8x+12)+32=0

We get rid of parentheses

-6x-8x-12+32=0

We add all the numbers together, and all the variables

-14x+20=0

We move all terms containing x to the left, all other terms to the right

-14x=-20

x=-20/-14

x=1+3/7

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