8-6(x-4)=2x-2(4x-3)+22

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Solution for 8-6(x-4)=2x-2(4x-3)+22 equation: 



8-6(x-4)=2x-2(4x-3)+22

We move all terms to the left:

8-6(x-4)-(2x-2(4x-3)+22)=0

We multiply parentheses

-6x-(2x-2(4x-3)+22)+24+8=0



We calculate terms in parentheses: -(2x-2(4x-3)+22), so:

2x-2(4x-3)+22

We multiply parentheses

2x-8x+6+22

We add all the numbers together, and all the variables

-6x+28

Back to the equation:

-(-6x+28)



We add all the numbers together, and all the variables

-6x-(-6x+28)+32=0

We get rid of parentheses

-6x+6x-28+32=0

We add all the numbers together, and all the variables

4!=0

There is no solution for this equation

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