8-6(x-4)=2x-2(4x-5)+22

Solution for 8-6(x-4)=2x-2(4x-5)+22 equation:

8-6(x-4)=2x-2(4x-5)+22

We move all terms to the left:

8-6(x-4)-(2x-2(4x-5)+22)=0

We multiply parentheses

-6x-(2x-2(4x-5)+22)+24+8=0


We calculate terms in parentheses: -(2x-2(4x-5)+22), so:

2x-2(4x-5)+22

We multiply parentheses

2x-8x+10+22

We add all the numbers together, and all the variables

-6x+32

Back to the equation:

-(-6x+32)


We add all the numbers together, and all the variables

-6x-(-6x+32)+32=0

We get rid of parentheses

-6x+6x-32+32=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0