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8-6x=4(1-2x)x=
We move all terms to the left:
8-6x-(4(1-2x)x)=0
We add all the numbers together, and all the variables
-6x-(4(-2x+1)x)+8=0
We calculate terms in parentheses: -(4(-2x+1)x), so:We get rid of parentheses
4(-2x+1)x
We multiply parentheses
-8x^2+4x
Back to the equation:
-(-8x^2+4x)
8x^2-4x-6x+8=0
We add all the numbers together, and all the variables
8x^2-10x+8=0
a = 8; b = -10; c = +8;
Δ = b2-4ac
Δ = -102-4·8·8
Δ = -156
Delta is less than zero, so there is no solution for the equation
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