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8-9t-4t^2=0
a = -4; b = -9; c = +8;
Δ = b2-4ac
Δ = -92-4·(-4)·8
Δ = 209
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{209}}{2*-4}=\frac{9-\sqrt{209}}{-8} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{209}}{2*-4}=\frac{9+\sqrt{209}}{-8} $
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