8-b=-11+3(b+5)

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Solution for 8-b=-11+3(b+5) equation: 



8-b=-11+3(b+5)

We move all terms to the left:

8-b-(-11+3(b+5))=0

We add all the numbers together, and all the variables

-1b-(-11+3(b+5))+8=0



We calculate terms in parentheses: -(-11+3(b+5)), so:

-11+3(b+5)

determiningTheFunctionDomain
3(b+5)-11

We multiply parentheses

3b+15-11

We add all the numbers together, and all the variables

3b+4

Back to the equation:

-(3b+4)



We get rid of parentheses

-1b-3b-4+8=0

We add all the numbers together, and all the variables

-4b+4=0

We move all terms containing b to the left, all other terms to the right

-4b=-4

b=-4/-4

b=1

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