8-x=1/2x+5

Solution for 8-x=1/2x+5 equation:

8-x=1/2x+5

We move all terms to the left:

8-x-(1/2x+5)=0


Domain of the equation: 2x+5)!=0

x∈R


We add all the numbers together, and all the variables

-1x-(1/2x+5)+8=0

We get rid of parentheses

-1x-1/2x-5+8=0

We multiply all the terms by the denominator


-1x*2x-5*2x+8*2x-1=0

Wy multiply elements

-2x^2-10x+16x-1=0

We add all the numbers together, and all the variables

-2x^2+6x-1=0

a = -2; b = 6; c = -1;
Δ = b2-4ac
Δ = 62-4·(-2)·(-1)
Δ = 28
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{28}=\sqrt{4*7}=\sqrt{4}*\sqrt{7}=2\sqrt{7}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{7}}{2*-2}=\frac{-6-2\sqrt{7}}{-4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{7}}{2*-2}=\frac{-6+2\sqrt{7}}{-4}
$