8-x=3x+(x-4)

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Solution for 8-x=3x+(x-4) equation: 



8-x=3x+(x-4)

We move all terms to the left:

8-x-(3x+(x-4))=0

We add all the numbers together, and all the variables

-1x-(3x+(x-4))+8=0



We calculate terms in parentheses: -(3x+(x-4)), so:

3x+(x-4)

We get rid of parentheses

3x+x-4

We add all the numbers together, and all the variables

4x-4

Back to the equation:

-(4x-4)



We get rid of parentheses

-1x-4x+4+8=0

We add all the numbers together, and all the variables

-5x+12=0

We move all terms containing x to the left, all other terms to the right

-5x=-12

x=-12/-5

x=2+2/5

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