8-y=2(y-2)

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Solution for 8-y=2(y-2) equation: 



8-y=2(y-2)

We move all terms to the left:

8-y-(2(y-2))=0

We add all the numbers together, and all the variables

-1y-(2(y-2))+8=0



We calculate terms in parentheses: -(2(y-2)), so:

2(y-2)

We multiply parentheses

2y-4

Back to the equation:

-(2y-4)



We get rid of parentheses

-1y-2y+4+8=0

We add all the numbers together, and all the variables

-3y+12=0

We move all terms containing y to the left, all other terms to the right

-3y=-12

y=-12/-3

y=+4

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