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8.15x^2-2.28x=0
a = 8.15; b = -2.28; c = 0;
Δ = b2-4ac
Δ = -2.282-4·8.15·0
Δ = 5.1984
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2.28)-\sqrt{5.1984}}{2*8.15}=\frac{2.28-\sqrt{5.1984}}{16.3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2.28)+\sqrt{5.1984}}{2*8.15}=\frac{2.28+\sqrt{5.1984}}{16.3} $
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