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8.5x-(x(2x-1))-3=0
We calculate terms in parentheses: -(x(2x-1)), so:We get rid of parentheses
x(2x-1)
We multiply parentheses
2x^2-1x
Back to the equation:
-(2x^2-1x)
-2x^2+8.5x+1x-3=0
We add all the numbers together, and all the variables
-2x^2+9.5x-3=0
a = -2; b = 9.5; c = -3;
Δ = b2-4ac
Δ = 9.52-4·(-2)·(-3)
Δ = 66.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9.5)-\sqrt{66.25}}{2*-2}=\frac{-9.5-\sqrt{66.25}}{-4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9.5)+\sqrt{66.25}}{2*-2}=\frac{-9.5+\sqrt{66.25}}{-4} $
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