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8.6x(2.2x^2x)=65
We move all terms to the left:
8.6x(2.2x^2x)-(65)=0
We multiply parentheses
16x^2-65=0
a = 16; b = 0; c = -65;
Δ = b2-4ac
Δ = 02-4·16·(-65)
Δ = 4160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4160}=\sqrt{64*65}=\sqrt{64}*\sqrt{65}=8\sqrt{65}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{65}}{2*16}=\frac{0-8\sqrt{65}}{32} =-\frac{8\sqrt{65}}{32} =-\frac{\sqrt{65}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{65}}{2*16}=\frac{0+8\sqrt{65}}{32} =\frac{8\sqrt{65}}{32} =\frac{\sqrt{65}}{4} $
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