8/(2x+3)=4/(x-1)

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Solution for 8/(2x+3)=4/(x-1) equation: 


D( x )

2*x+3 = 0

x-1 = 0

2*x+3 = 0

2*x+3 = 0

2*x+3 = 0 // - 3

2*x = -3 // : 2

x = -3/2

x-1 = 0

x-1 = 0

x-1 = 0 // + 1

x = 1

x in (-oo:-3/2) U (-3/2:1) U (1:+oo)

8/(2*x+3) = 4/(x-1) // - 4/(x-1)

8/(2*x+3)-(4/(x-1)) = 0

8/(2*x+3)-4*(x-1)^-1 = 0

8/(2*x+3)-4/(x-1) = 0

(8*(x-1))/((2*x+3)*(x-1))+(-4*(2*x+3))/((2*x+3)*(x-1)) = 0

8*(x-1)-4*(2*x+3) = 0

-20 = 0

-20/((2*x+3)*(x-1)) = 0

-20/((2*x+3)*(x-1)) = 0 // * (2*x+3)*(x-1)

-20 = 0

x belongs to the empty set

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