8/(2x-4)=3

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Solution for 8/(2x-4)=3 equation: 



8/(2x-4)=3

We move all terms to the left:

8/(2x-4)-(3)=0



Domain of the equation: (2x-4)!=0

We move all terms containing x to the left, all other terms to the right

2x!=4

x!=4/2

x!=2

x∈R



We multiply all the terms by the denominator


-3*(2x-4)+8=0

We multiply parentheses

-6x+12+8=0

We add all the numbers together, and all the variables

-6x+20=0

We move all terms containing x to the left, all other terms to the right

-6x=-20

x=-20/-6

x=3+1/3

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