8/(2x-7)=40/(7x-1)

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Solution for 8/(2x-7)=40/(7x-1) equation: 


D( x )

2*x-7 = 0

7*x-1 = 0

2*x-7 = 0

2*x-7 = 0

2*x-7 = 0 // + 7

2*x = 7 // : 2

x = 7/2

7*x-1 = 0

7*x-1 = 0

7*x-1 = 0 // + 1

7*x = 1 // : 7

x = 1/7

x in (-oo:1/7) U (1/7:7/2) U (7/2:+oo)

8/(2*x-7) = 40/(7*x-1) // - 40/(7*x-1)

8/(2*x-7)-(40/(7*x-1)) = 0

8/(2*x-7)-40*(7*x-1)^-1 = 0

8/(2*x-7)-40/(7*x-1) = 0

(8*(7*x-1))/((2*x-7)*(7*x-1))+(-40*(2*x-7))/((2*x-7)*(7*x-1)) = 0

8*(7*x-1)-40*(2*x-7) = 0

272-24*x = 0

(272-24*x)/((2*x-7)*(7*x-1)) = 0

(272-24*x)/((2*x-7)*(7*x-1)) = 0 // * (2*x-7)*(7*x-1)

272-24*x = 0

272-24*x = 0 // - 272

-24*x = -272 // : -24

x = -272/(-24)

x = 34/3

x = 34/3

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