8/(4+m)+8/m=1

Solution for 8/(4+m)+8/m=1 equation:

8/(4+m)+8/m=1

We move all terms to the left:

8/(4+m)+8/m-(1)=0


Domain of the equation: (4+m)!=0

We move all terms containing m to the left, all other terms to the right

m!=-4

m∈R



Domain of the equation: m!=0

m∈R


We add all the numbers together, and all the variables

8/(m+4)+8/m-1=0

We calculate fractions


8m/(m^2+4m)+(8m+32)/(m^2+4m)-1=0

We multiply all the terms by the denominator


8m+(8m+32)-1*(m^2+4m)=0

We get rid of parentheses

8m+8m-1*(m^2+4m)+32=0

We add all the numbers together, and all the variables

16m-1*(m^2+4m)+32=0

We move all terms containing m to the left, all other terms to the right

16m-1*(m^2+4m)=-32